Area - Quantitative Aptitude
Q21. Each side of an equilateral triangle is 42 cm. What is the area of the circle inscribed in it ?
(a) 332 cm2
(b) 359 cm2
(c) 423 cm2
(d) 462 cm2
Answer: (d) 462 cm2
Area of the triangle = | √3 | X a2 = | √3 | X 42 X 42 cm2 = 21 X 21 X √3 cm2 |
4 | 4 |
s = | 42 + 42 + 42 | = 63 |
3 |
Radius of the triangle = | Δ | = | 21 X 21 X √3 | = 7√3 |
s | 63 |
∴ Area of the circle = π r2 = | 22 | X 7√3 X 7√3 = 462 cm2 |
7 |
Q22. The length of a rectangular plot is 4½ times that of its breadth. If the area of the plot is 200 square meter, then what is its length ?
(a) 24 m
(b) 25 m
(c) 27 m
(d) 30 m
Answer: (d) 30 m
Let, the breadth be x m
∴ the length = 4½ X x m = 9x/2
A/Q x X | 9x | = 200 |
2 |
⇒ 9x2 = 400
⇒ x = √(400/9) = | 20 |
3 |
∴ Length = | 9 | X | 20 | = 30 m |
2 | 3 |
Q23. The area of a rectangle is 12 sq meters and its length is 3 times that of its breadth. What is the perimeter of the rectangle ?
(a) 16 m
(b) 19 m
(c) 21 m
(d) 24 m
Answer: (a) 16 m
Let, the breadth be x m
∴ the length = 3x m
A/Q x X 3x = 12
⇒ x2 = 4
⇒ x = 2
∴ length = 3 X 2 = 6 m
breadth = 2 m
∴ Perimeter = 2 (6 + 2) = 16 m
Q24. A road of uniform width runs round the inside of a rectangular field 38 m long and 32 m wide. If the road occupies 600 m2, the width of the road is
(a) 4 m
(b) 5 m
(c) 6 m
(d) 8 m
Answer: (b) 5 m
Area of the field = 38 X 32 m2 = 1216 m2
Let the width of the road be x m
∴ Area without road = (38 - 2x)(32 - 2x) m2 = 1216 + 4x2 - 140x
Area of the road = 1216 - (1216 + 4x2 - 140x)
⇒ 600 = 140x - 4x2
⇒ 4x2 - 140x + 600 = 0
⇒ x2 - 35x + 150 = 0
⇒ (x - 30)(x - 5) = 0
∴ x = 5 m
Q25. The area of a triangle is x square cm. and its base is y cm. What is the height of the triangle ?
(a) x/y cm
(b) x/2y cm
(c) 2x/y cm
(d) 2x2/y cm
Answer: (c) 2x/y cm
Area = ½ X base X height
⇒ x = ½ X y X height
⇒ height = 2x/y cm
Q26. The two parallel sides of a trapezium are 2 cm and 4 cm respectively and the perpendicular distance between them is 3 cm. The area of the trapezium is
(a) 6 cm2
(b) 7 cm2
(c) 8 cm2
(d) 9 cm2
Answer: (d) 9 cm2
Area = ½ X (2 + 4) X 3 cm2
= ½ X 6 X 3 cm2 = 9 cm2
Q27. What is the area of an equilateral triangle inscribed in a circle of unit radius ?
(a) 2√2/3 sq unit
(b) 3√3/4 sq unit
(c) 3√2/4 sq unit
(d) 4√3/3 sq unit
Answer: (b) 3√3/4 sq unit
Let each side of the triangle be x
Now radius = x/√3
⇒ 1 = x/√3
⇒ x = √3
∴ Area = | √3 | X (√3)2 = | √3 | X 3 = | 3√3 | sq unit |
4 | 4 | 4 |
Q28. A rectangular courtyard 3.78 m long and 5.25 m broad is to be paved exactly with square tiles, all of the same size. The minimum number of such tiles is
(a) 402
(b) 415
(c) 425
(d) 450
Answer: (d) 450
l = 3.78 m = 378 cm
b = 5.25 m = 525 cm
Maximum length of a square tile = H.C.F of 378, 525 = 21 cm
∴ No of tiles = | 378 X 525 | = 450 |
21 X 4 |
Q29. The perimeter of a rectangle and a square are 160 m each. The area of the recctangle is less than that of the square by 100 sq meters. The length of the rectangle is
(a) 50 m
(b) 65 m
(c) 72 m
(d) 76 m
Answer: (a) 50 m
Perimeter of the square = 4 X side
⇒ 160 = 4 X side
⇒ side = 40 m
Area of the square = side2 = 40 X 40 = 1600 squaremeter
Area of the rectangle = l X b
A/Q lb + 100 = 1600
⇒ lb = 1500
A/Q 2(l + b) = 160
⇒ l + b = 80 ------ (1)
Now, (l - b)2 = (l + b)2 - 4lb = 802 - 4 X 1500 = 400
∴ l - b = 20 ------ (2)
(1) + (2) ⇒ 2l = 100 ⇒ l = 50 m
Q30. If the ratio of the areas of two squares is 16 : 1, then the ratio of their perimeter is
(a) 2:1
(b) 3:1
(c) 4:1
(d) 5:1
Answer: (c) 4:1
Let the area of the squares be 16x2, x2
∴ Each side of the 1st square = 4x
Each side of the 2nd square = x
Perimeter of the 1st square = 4 X 4x = 16x
Perimeter of the 2nd square = 4 X x = 4x
∴ Ratio of the perimeter = 16x : 4x = 4 : 1
Practice Test Exam