Problems on Times and Distance
Q1. A man is walking at a speed of 10 km/hr. After every
kilometer, he takes rest for 4 minutes. How much time will
he take to cover a distance of 10 km ?
(a) 96 minutes
(b) 100 minutes
(c) 60 minutes
(d) 90 minutes
Answer:(a) 96 minutes
For travelling 10 km he will take rest 9 times each of 4 minutes
So the total time taken to travell 10 km
=60 + 36
=96 minutes
Q2. A car completes a journey in 11 hours, the first half
at 30 km/hr and the second half at 25 km/hr. Find the
distance travelled ?
(a) 250 km
(b) 375 km
(c) 300 km
(d) 400 km
Answer:(c) 300 km
Let the distance travelled be x km
(x/(2X30)) + (x/(2X25)) = 11
x/60 + x/50 = 11
(5x + 6x) / 300 = 11
x = 300 km
Q3. A car moves at the speed of 72 km/hr. What is the
speed of the bus in metres per second ?
(a) 15 metre/sec
(b) 18 metre/sec
(c) 20 metre/sec
(d) 26 metre/sec
Answer:(c) 20 metre/sec
Speed of the car = 72 X (5/18) = 20 metre/sec
Q4. A car moving at the speed of 36 km/hr crosses a
bridge in 5 minutes. What is the length of the bridge in
metres ?
(a) 2000 metres
(b) 3000 metres
(c) 3500 metres
(d) 4500 metres
Answer: (b) 3000 metres
Speed of the car = 36 X (5/18) = 10 metre/sec
5 minutes = 5 X 60 = 300 sec
Distance covered in 5 minutes (300 sec) = (10 X 300) = 3000 metres
Q5. If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is
(a) 30 Km
(b) 45 Km
(c) 50 Km
(d) 60 Km
Answer: (c) 50 Km
Let the actual distance travelled be x km. Then
x/10 = (x+20)/14
14x = 10x + 200
4x = 200
x = 50 Km
Q6. A car starts a journey of 290 km with the speed of 50 km/hr. After every two hours the speed of the car increase by 10 km/hr. So how much time will it take to cover the distance
(a) 2 hr 10 min
(b) 4 hr
(c) 4 hr 45 min
(d) 5 hr
Answer: (d) 5 hr
Distance covered in first 2 hr = (50 X2) = 100 Km
Distance covered in nect 2 hr = (60 X2) = 120 Km
So total distance covered in 4 hr = (100+120)= 220 Km
Remainaing distnace = (290 - 220) = 70 km
Speed in 5th hr = 70 km/hr
So total time taken = (4hr + 1hr) = 5hr
Q7. A is twice as fast as B and B is thrice as fast as C. The journey covered by C in 42 minutes will be covered by A in
(a) 7 minutes
(b) 14 minutes
(c) 16 minutes
(d) 20 minutes
Answer: (a) 7 minutes
A taken time 1/2 of B i.e B/2
B taken time 1/3 of C i.e C/3
C take time = 42 minutes
∴ B takes time = (42/3) = 14 minutes
∴ A takes time = 14/2 minutes = 7 minutes
Q8. A man performs 4/15 of the total journey by rail, 9/20 by bus and the remaining 5 km by walking. His total journey is
(a) 16 km
(b) 17.647 km
(c) 17.476 km
(d) 17.764 km
Answer: (b) 17.647 km
Let the total journey be x km
∴ x(4/15) + x(9/20) + 5 = x
=> | 4x | + | 9x | + 5 = x |
15 | 20 |
=> | 80x + 135x +1500 | = x |
300 |
=> 215x = 300x - 1500
=> 300x - 215x = 1500
=> 85x = 1500
=> x = 1500/85 = 17.647 km
Q9. The speeds of three cars are in the ratio 2 : 3 : 5. The ratio of the times taken by these cars to travel the same distance is
(a) 2 : 3 : 5
(b) 3 : 2 : 5
(c) 4 : 6 : 10
(d) 15 : 10 : 6
Answer: (d) 15 : 10 : 6
Ratio of the time taken = | 1 | : | 1 | : | 1 |
2 | 3 | 5 |
= | 1 | X 30 : | 1 | X 30 : | 1 | X 30 |
2 | 3 | 5 |
= 15 : 10 : 6
Q10. A police is 108 m behind a thief. The police runs 21 m and the thief run 15 m in a minute. In what time will the police catch the thief
(a) 12 minute
(b) 16 minute
(c) 18 minute
(d) 20 minute
Answer: (c) 18 minute
(21 - 15) m = 6m covered in 1 minute
∴ 108m covered in (108/6) minutes = 18 minutes
Practice Test Exam